Implementation of DFA 5
/1
0
case
state
of
s : begin
{
start state
}
...
if symbol =
'<'
then
state
:= f6
;
else
if symbol =
'{'
then
state
:= p
;
end; {state s}
14
/35
s
<
f
6
<
=
f
7
<=
>
f
8
< >
{
}
S
–
}
p